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The mole and concentration of solutionsConcentration of solutions

The gram formula mass of a substance is known as the mass of one mole. The mass, number of moles, concentration or volume of a substance can be calculated easily if you learn two formula triangles.

Part of ChemistryChemical changes and structures

Concentration of solutions

Solutions are formed when solutes dissolve in solvents. If the number of moles of solute and the volume of solvent used is known, the concentration of the solution can be calculated.

The concentration of a solution is measured in moles per litre (mol l-1) and can be calculated using this formula triangle:

An equilateral triangle pointing upwards and divided into three parts. The top part represents the number of moles. The bottom left part represents the concentration in moles per litre. The bottom right part represents the volume in litres.

Using the formula triangle gives three useful formulae:

\(concentration = \frac{{no.\,of\,moles}}{{volume}}\)

\(volume = \frac{{no.\,of\,moles}}{{concentration}}\)

\(no.\,of\,moles = concentration \times volume\)

Example one

Calculate the concentration of the solution formed when 0.25 moles of potassium nitrate are dissolved in 500 cm3 of water.

The formula we need to use, given by covering up concentration is:

\(concentration = \frac{{no.\,of\,moles}}{{volume}}\)

\(= \frac{{0.25}}{{0.5}}\)

\(=0.5\,mol\,l_{}^{ - 1}\)

Remember that the volume always has to be changed into litres.

Example two

Calculate the number of moles in 200cm3 of 0.5 mol l-1 sodium hydroxide (NaOH) solution.

\(number\,of\,moles = concentration \times volume\,(in\,litres)\)

\(\begin{array}{l} = 0.5 \times 0.2\\ = 0.1\,moles \end{array}\)

Example three

Calculate the volume of sodium hydroxide used in 1 mol l-1 solution containing 2 mol of solute.

\(volume = \frac{{number\,of\,moles}}{{concentration}}\)

\(= \frac{2}{1}\)

\(= 2l\)

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