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Divide \(8932\) by \(7\) (\(8932 \div 7\))

1. Start with the \(8\) in the thousands column. \(7\) into \(8\) goes \(1\) time remainder \(1\). Put the remainder next to the \(9\) in the hundreds column (now \(19\)) and the other \(1\) in the answer again in the thousands column.
2. Go to the \('19'\) in the hundreds column. \(7\) into \(19\) goes \(2\) times remainder \(5\). Put the remainder next to the \(3\) in the tens column (now \(53\)) and the \(2\) in the answer in the hundreds column.
3. Go to the \('53'\) in the tens column. \(7\) into \(53\) goes \(7\) times remainder \(4\). Put the remainder next to the \(2\) in the units column (now \(42\)) and the \(7\) in the answer in the tens column.
4. Go to the \('42'\) in the units column. \(7\) into \(42\) goes \(6\) times with no remainder. Put the \(6\) in the answer in the units column

Therefore \(8932 \div 7 = 1276\)

Divide \(346\) by \(8\) (\(346 \div 8\))

1. Same procedure as above until the \(6\) in the units column.
2. \(8\) into \(26\) goes \(3\) times remainder \(2\). As there are no digits after the \(6\) you must now put in \(0\) as a digit after the decimal point. A decimal point must now also be included in your answer. The remainder \(2\) is now put next to the \(0\) after the decimal point (now \(20\)).
3. Go to the \('20'\) in the tenths column. \(8\) into \(20\) goes \(2\) times remainder \(4\).
4. Introduce a \(0\) in the hundredths column and put the remainder \(4\) next to this (now \(40\)). The \(2\) goes in the tenths column of the answer.
5. \(8\) into \('40'\) goes \(5\) times with no remainder. The \(5\) goes in the answer in the hundredths column.

Therefore \(346 \div 8 = 43 \cdot 25\)

Divide \(225.75\) by \(7\) (\(225.75 \div 7\))

1. Place decimal point of solution above the decimal point of the original number.
2. \(7\) into \(22\) goes \(3\) times remainder \(1\). Put the remainder next to the \(5\) in the units column (now \(15\)) and the \(3\) in the answer in the tens column.
3. \(7\) into \('15'\) goes \(2\) times remainder \(1\). Put the remainder next to the \(7\) in the tenths column (now \(17\)) and the \(2\) in the answer in the units column.
4. \(7\) into \('17'\) goes \(2\) times remainder \(3\). Put the remainder next to the \(5\) in the hundredths column (now \(35\)) and the \(2\) in the answer in the tenths column.
5. \(7\) into \('35'\) goes \(5\) times with no remainder. The \(5\) goes in the answer in the hundredths column.

Therefore \(225 \cdot 75 \div 7 = 32 \cdot 25\)