Creu siart cylch
Creu siartiau cylch 鈥 defnyddio tabl
Mae鈥檙 tabl isod yn dangos y marciau a enillwyd gan \({30}\) o ddisgyblion yn eu harholiad diwedd tymor.
I ddangos y wybodaeth hon mewn siart cylch, cymera鈥檙 camau canlynol:
- Cyfrifa gyfanswm nifer y disgyblion: \({7} + {11} + {6} + {4} + {2} = {30}\)
- I gyfrifo ongl pob segment, cyfrifa pa ffracsiwn o鈥檙 cyfanswm a gafodd bob marc.
- Dechreua gyda marciau A: \(\frac{7}{30}\)
- Mae \({360}^\circ\) mewn cylch llawn, felly i ganfod yr ongl, lluosa鈥檙 ffracsiwn 芒 \({360}:\frac{7}{30}\times{360} = {84}^\circ\)
- Mae gan sector marciau A ongl o \({84}^\circ\).
- Dilyna'r un broses i ganfod ongl segmentau鈥檙 marciau eraill.
- Unwaith y byddi di wedi cyfrifo onglau鈥檙 segmentau, cer ati i greu'r siart cylch.
Question
Cop茂a a chwblha鈥檙 tabl isod, wedyn defnyddia鈥檙 data i greu siart cylch.
Marc | Amlder | Ongl |
A | \({7}\) | \(\frac{7}{30}\times{360}={84}^\circ\) |
B | \({11}\) | |
C | \({6}\) | |
D | \({4}\) | |
E | \({2}\) |
Marc | A |
---|---|
Amlder | \({7}\) |
Ongl | \(\frac{7}{30}\times{360}={84}^\circ\) |
Marc | B |
---|---|
Amlder | \({11}\) |
Ongl |
Marc | C |
---|---|
Amlder | \({6}\) |
Ongl |
Marc | D |
---|---|
Amlder | \({4}\) |
Ongl |
Marc | E |
---|---|
Amlder | \({2}\) |
Ongl |
Marc | Amlder | Ongl |
A | \({7}\) | \(\frac{7}{30}\times{360}= {84}^\circ\) |
B | \({11}\) | \(\frac{11}{30}\times{360} = {132}^\circ\) |
C | \({6}\) | \(\frac{6}{30}\times{360} = {72}^\circ\) |
D | \({4}\) | \(\frac{4}{30}\times{360} = {48}^\circ\) |
E | \({2}\) | \(\frac{2}{30}\times{360} = {24}^\circ\) |
Marc | A |
---|---|
Amlder | \({7}\) |
Ongl | \(\frac{7}{30}\times{360}= {84}^\circ\) |
Marc | B |
---|---|
Amlder | \({11}\) |
Ongl | \(\frac{11}{30}\times{360} = {132}^\circ\) |
Marc | C |
---|---|
Amlder | \({6}\) |
Ongl | \(\frac{6}{30}\times{360} = {72}^\circ\) |
Marc | D |
---|---|
Amlder | \({4}\) |
Ongl | \(\frac{4}{30}\times{360} = {48}^\circ\) |
Marc | E |
---|---|
Amlder | \({2}\) |
Ongl | \(\frac{2}{30}\times{360} = {24}^\circ\) |