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Energy changes in chemical reactionsBond energy calculations

The changes in energy that occur during a chemical reaction can be seen by examining the changes in chemical bonding. This can be used to classify reactions as exothermic or endothermic.

Part of Chemistry (Single Science)Chemical reactions and energy

Bond energy calculations

You can calculate the energy change in a reaction using average bond energies. Bond energy is the amount of energy needed to break one of a particular bond.

To calculate bond energy

  1. Add together the bond energies for all the bonds in the 鈥 this is the 鈥榚nergy in鈥.
  2. Add together the bond energies for all the bonds in the 鈥 this is the 鈥榚nergy out鈥.
  3. Calculate the energy change = energy in 鈥 energy out.

Worked example 鈥 an exothermic reaction

Hydrogen and chlorine react to form hydrogen chloride gas:

贬鈭扝 + 颁濒鈭扖濒 鈫 2 脳 (贬鈭扖濒)

BondBond energy (kJ/mol)
贬鈭扝436
颁濒鈭扖濒243
贬鈭扖濒432
Bond贬鈭扝
Bond energy (kJ/mol)436
Bond颁濒鈭扖濒
Bond energy (kJ/mol)243
Bond贬鈭扖濒
Bond energy (kJ/mol)432
  1. Energy in = 436 + 243 = 679 kJ/mol (this is the energy absorbed when the bonds of the reactants break).
  2. Energy out = 2 脳 432 = 864 kJ/mol (this is the energy released when the bonds of the products form).
  3. Energy change = in 鈥 out = 679 鈥 864 = 鈥185 kJ/mol

The energy change is negative, due to the fact that the energy released by the bonds formed is greater than the energy absorbed by the bonds broken. This means that energy is released to the surroundings in an reaction.

Worked example 鈥 calculating bond energy [Higher tier only]

Hydrogen reacts with iodine to form hydrogen iodide.

贬鈭扝 + 滨鈭扞 鈫 2 脳 (H鈥揑)

BondBond Energy (kJ/mol)
贬鈭扞?
贬鈭扝436
滨鈭扞151
Bond贬鈭扞
Bond Energy (kJ/mol)?
Bond贬鈭扝
Bond Energy (kJ/mol)436
Bond滨鈭扞
Bond Energy (kJ/mol)151

The energy change for this reaction is 鈥3 kJ/mol. Calculate the bond energy of the H鈥揑 bond.

  1. Energy in = 436 + 151 = 587 kJ/mol
  2. Energy out = 2 脳 (bond energy of H鈥揑) = 2(H鈥揑)
  3. Energy change = in 鈥 out = 587 鈥 2(H鈥揑) = 鈥3 kJ/mol
  4. Rearrange to: 2(H鈥揑) = 587 + 3 = 590 kJ/mol
  5. Therefore: (H鈥揑) = 590 梅 2 = 295 kJ/mol