大象传媒

Semi-interquartile range

The semi-interquartile range is half of the difference between the upper quartile and the lower quartile.

In the previous example, the quartiles were \(Q_1 = 4\) and \(Q_3 = 11\).

The semi-interquartile range is:

\(\frac{1}{2}\,(Q_3 - Q_1)\)

\(=\frac{1}{2}\,\times\,(11-4) \)

\(\frac{1}{2}\,\times \,(11-4)\)

\(=\frac{1}{2}\,\times \,7=3.5\)

Example

A survey was carried out to find the number of pets owned by each child in a class. The results are given below:

Number of petsFrequency
03
15
22
37
410
53
61
Number of pets0
Frequency3
Number of pets1
Frequency5
Number of pets2
Frequency2
Number of pets3
Frequency7
Number of pets4
Frequency10
Number of pets5
Frequency3
Number of pets6
Frequency1

Find the semi-interquartile range.

Answer

Adding a cumulative frequency column is helpful for finding median and quartiles.

Number of petsFrequencyCumulative Frequency
033
158
2210
3717
41027
5330
6131
Number of pets0
Frequency3
Cumulative Frequency3
Number of pets1
Frequency5
Cumulative Frequency8
Number of pets2
Frequency2
Cumulative Frequency10
Number of pets3
Frequency7
Cumulative Frequency17
Number of pets4
Frequency10
Cumulative Frequency27
Number of pets5
Frequency3
Cumulative Frequency30
Number of pets6
Frequency1
Cumulative Frequency31

There are 31 children in the class.

The lower quartile is the \((31+1)\div 4\) value which is the \(8^{th}\) value, which is \(1\).

The upper quartile is the \((31+1)\div 4\,\times 3=24^{th}\) value, which is \(4\).

Therefore the semi-interquartile range is \(\frac{1}{2}\times (4-1)=1.5\)

(Sometimes you are asked for the interquartile range. If so, then you do not half the answer to \(Q_3 - Q_1\). In the above example the interquartile range is \(3\)).

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