大象传媒

Force and Newton's laws - CCEANewton's Second Law

In 1687, Isaac Newton created three laws of motion to describe the relationship between a body and the forces acting upon it, and how the body moves in response to those forces.

Part of Physics (Single Science)Force

Newton's Second Law

Newton鈥檚 Second Law follows from the results of the above experiments.

The relationship between the , the of the object and the object鈥檚 is:

Resultant force F = mass m x acceleration a

F = ma

F = resultant force in N

m = mass in kg

a = acceleration on m/s2

A formula triangle showing Force is equal to Mass multiplied by Acceleration.
\({F} = {ma}\)\({F} = {m}\times{a}\)
\({m} =\frac{\text{F}}{\text{a}}\)\({m} = {F} \div {a}\)
\({a} = \frac{\text{F}}{\text{m}}\)\({a} = {F} \div {m}\)
\({F} = {ma}\)
\({F} = {m}\times{a}\)
\({m} =\frac{\text{F}}{\text{a}}\)
\({m} = {F} \div {a}\)
\({a} = \frac{\text{F}}{\text{m}}\)
\({a} = {F} \div {m}\)

The newton N

The unit of force is the newton N.

One newton is the resultant force that gives a mass of 1 kg an acceleration of 1 m/s2 in the direction of the force.

1 N = 1 kg x 1 m/s2

Example

A car has a mass of 1000 kg and a resultant force of 5000 N acts on it.

Question

What is the acceleration of the car?

In the example below two forces act on the car.

To calculate the acceleration, the resultant of the forces must first be found.

A car with 2 forces acting either side of it. On the left is Thrust of 4,000 newtons, on the right is Drag of 5,000 newtons.

a = \(\frac{\text{F}}{\text{m}}\)

The resultant force F = 4000 N - 1000 N

= 3000 N

F = 3000 N

m = 1000 kg

a = \(\frac{\text{3000 N}}{\text{1000 kg}}\)

a = 3 m/s2

The car accelerates because the car is moving in the same direction as the resultant force.

Now look at a second example. The forward force remains at 4000 N.

A car with 2 forces acting either side of it. The car is moving to the left. On the right there is a drag of 7,000 newtons (air resistance & braking).

a = \(\frac{\text{F}}{\text{m}}\)

The resultant force F = 4000 N - 7000 N = -3000 N

F = -3000 N

m = 1000 kg

a = \(\frac{\text{-3000 N}}{\text{1000 kg}}\)

a = -3 m/s2

The car now has an acceleration of -3 m/s2 or a deceleration of 3 m/s2.

It is moving in the opposite direction to the resultant force and slows down.