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Calculating yields - OCR 21st CenturyTheoretical yield

The percentage yield shows how much product is obtained compared to the maximum possible mass. Molar gas volume can be used to make calculations about reactions between gases.

Part of Chemistry (Single Science)Chemical analysis

Theoretical yield

The is the maximum possible of a that can be made in a chemical reaction.

It can be calculated from:

  • the
  • the mass and of the , and
  • the relative formula mass of the product

An is the mass of a product actually obtained from the reaction. It is usually less than the theoretical yield. The reasons for this include:

  • incomplete reactions, in which some of the do not react to form the product
  • practical losses during the experiment, such as during pouring or
  • side reactions (unwanted reactions that compete with the desired reaction)
  • in reactants

Calculating theoretical yield

Reacting masses may be used to calculate the theoretical yield. Theoretical yield can also be worked out using a calculation.

Worked example

If heated, calcium carbonate to form calcium oxide and carbon dioxide.

Calculate the maximum theoretical yield of calcium oxide that can be produced from 250 g of calcium carbonate.

  1. Write down the balanced chemical equation:
    • CaCO3\(\rightarrow\) CaO + CO2
  2. Calculate the relative formula masses of the substances in the question:
    • Mr of CaCO3 = 40.1 + 12.0 + (3 脳 16.0) = 100.1
    • Mr of CaO = 40.1 + 16.0 = 56.1
  3. Use the balanced chemical equation to work out the reacting masses based on the relative formula masses:
    • 100.1 g CaCO3 produces 56.1 g of CaO
  4. Work out the reacting masses for 1 g (or 1 kg or 1 tonne if different mass units are used):
    • \(\frac{100.1}{100.1}\) = 1 g of CaCO3 produces \(\frac{56.1}{100.1}\) g of CaO
  5. Scale up the reacting masses to match the given reacting mass of the reactant:
    • 250 g of CaCO3 produces \(\frac{56.1}{100.1}\) x 250
    • = 140 g of CaO