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Monitoring and measuring a.c.Root mean square (r.m.s.) voltages and currents

a.c. is current which changes direction and instantaneous value with time. Peak or r.m.s. values can be calculated if the other is known. Frequency can be determined from graphical data.

Part of PhysicsElectricity

Root mean square (r.m.s.) voltages and currents

The r.m.s. value of an a.c. signal is equal to the value of direct current (d.c.) which would have the same effect or energy change as the a.c.

For example if a 12 car battery operated a light bulb of 36 with direct current, an a.c. supply would need to be set to 12 V r.m.s. to achieve the same 36 W power output.

The r.m.s. voltage of an a.c. signal is always less than peak voltage because the peak voltage only occurs twice in the cycle (one positive one negative, during the rest of the cycle). At other times it is less!

To calculate the r.m.s. voltage from the peak voltage the factor of \(\frac{1}{\sqrt2}\) is used.

\(V_{rms}=\frac{V_{peak}}{\sqrt2}\)

There is a similar between r.m.s. and peak current.

\(I_{rms}=\frac{I_{peak}}{\sqrt2}\)

For example the mains voltage in the UK can vary between 216 and 253 volts. These are r.m.s. values. To calculate the maximum possible voltage from a socket the peak voltage for 253 volts r.m.s. is:

\(V_{peak}=\sqrt2\,V_{rms}\)

\(=1.41\times253\)

\(V_{peak} = 358V\)

All mains appliances must be designed to operate safely at this peak voltage even though it only happens twice every 0.02 seconds!

Question

How does the peak power developed by an a.c. appliance compare to the r.m.s. power?