General method
Divide \(8932\) by \(7\) - \((8932 \div 7)\).
- Start with dividing the \(8\) in the thousands column by \(7\). It goes \(1\) time remainder \(1\). Put \(1\) in the answer in the thousands column and the remainder next to the \(9\) in the hundreds column (now \(19\)).
- Divide \(7\) into the '\(19\)' in the hundreds column. It goes \(2\) times remainder \(5\). Put the \(2\) in the answer in the hundreds column and the remainder next to the \(3\) in the tens column (now \(53\)).
- Divide \(7\) into the '\(53\)' in the tens column. It goes \(7\) times remainder \(4\). Put the \(7\) in the answer in the tens column and the remainder next to the \(2\) in the units column (now \(42\)).
- Divide \(7\) into the '\(42\)' in the units column. It goes \(6\) times with no remainder. Put the \(6\) in the answer in the units column.
Therefore \(8932 \div 7 = 1276\)
Now try the example question below.
Question
Divide \(346\) by \(8\) - \((346 \div 8)\)
- Use the same procedure as above until you get to the \(6\) in the units column.
- We get \(8\) into \(26\) goes \(3\) times remainder \(2\). As there are no digits after the \(6\) you must now put in \(0\) as a digit after the decimal point. A decimal point must now also be included in your answer. The remainder \(2\) is now put next to the \(0\) after the decimal point (now \(20\)).
- Divide \(8\) into the '\(20\)' in the tenths column. It goes \(2\) times remainder \(4\).
- The \(2\) goes in the tenths column of the answer. Introduce a \(0\) in the hundredths column and put the remainder \(4\) next to this (now \(40\)).
- We get \(8\) into '\(40\)' goes \(5\) times with no remainder. The \(5\) goes in the answer in the hundredths column.
Therefore \(346 \div 8 = 43 \cdot 25\)