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Gas volume

If a balloon is squeezed it will get smaller. If the is increased, the will decrease.

J-shaped glass tube, filled with mercury, and a trapped air bubble at the smaller end.

The Irish scientist, Robert Boyle, originally investigated this relationship in the 17th century. Boyle carried out an experiment that provided one of the first pieces of experimental evidence for the .

By pouring mercury into a J-shaped tube that was sealed at one end, Boyle was able to trap a bubble of air. He then poured more mercury in slowly and watched what happened to the volume of the air bubble.

The higher the column of mercury in the left hand side of the tube, the greater the pressure the trapped air was experiencing and the smaller the bubble became.

So, if there are two situations for a fixed mass of gas held at a constant temperature then:

p1V1 = p2V2

This is when:

  • initial pressure, (p1), changes to a second pressure (p2) at the same time as
  • initial volume, (V1), changes to a second volume (V2).

This relationship works for any units as long as the same units are used in situations 1 and 2. Normally:

  • pressure (p) is measured in pascals (Pa)
  • volume (V) is measured in cubic metres (m3)

If the of a gas stays the same, the pressure of the gas increases as the volume of its container decreases. This is because the same number of particles collides with the walls of the container more frequently as there is less space. However, the particles still collide with the same amount of force.

Example

A gas occupies a volume of 0.50 m3 at a pressure of 100 Pa. Calculate the pressure exerted by the gas if it is compressed to a volume of 0.25 m3. Assume that the temperature and mass of the gas stay the same.

Rearrange p1 V1 = p2 V2 to find p2:

\(p_{2} = \frac{p_{1} \times V_{1}} {V_{2}}\)

\(p_{2} = \frac{100 \times 0.50}{0.25}\)

New pressure, p2 = 200 Pa

Question

If a gas has a pressure of 200,000 Pa when it is in a volume of 10 m3, what will its pressure be if the volume is reduced to 2.5 m3?