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Problem 1 - Books and magazines

Problem 1 is all about working out how many books there are in different boxes.

Maths teacher Chris Smith and pupils from Grange Academy are here to explain.

The Maths Week Scotland Daily Challenges have been set by the Scottish Mathematical Council.

So here's the challenge:

Eilidh is a second-hand bookseller and she needs to clear some space in her shop.

She has six boxes of books and one box of magazines she wants to move.

Each box shows how many items there are in it. The boxes hold 24, 19, 17, 20, 25, 16 and 16 items.

Eilidh has six boxes. They have different numbers of items in them: 24, 19, 17, 20, 25, 16, 16
Image caption,
Eilidh has seven boxes and we know how many items are in each box but we don't know which one contains magazines.

Eilidh makes the space she needs by:

  • selling off some books to one customer
  • twice that number to another customer
  • keeping the magazines for herself

Can you work out how many magazines Eilidh held on to?

Need a hint?

  • What can you work out about the total number of books?
  • Can you work out how many books each customer buys?
  • Can you find different totals by adding different boxes together?

Solution

Worked out the answer? Here's how you can do it.

Six boxes of books added together equals a multiple of three

One customer buys twice as many books as the other. Between the two customers they buy three times a certain number of books.

The total number of books must be a multiple of three, so that it divides by three to give a whole number.

Six boxes of books added together equals a multiple of three
Bookseller in shop. Equation shows the total number of books is 137. This divides by 3 to give 45 remainder 2. Magazines divided by 3 gives an unknown number remainder 2.

Step 1

Find the total number of books and magazines:

16 + 20 + 19 + 24 + 17 + 25 + 16 = 137

Step 2

Divide the total by three:

137 梅 3 = 45 remainder 2

We know that the total number of books is a multiple of three. This means if the number of magazines is divided by three it would also leave a remainder of two.

Bookseller in shop. Equation shows the total number of books is 137. This divides by 3 to give 45 remainder 2. Magazines divided by 3 gives an unknown number remainder 2.
16, 20, 19, 24, 25 and 25 are divided by 3. Only 20 and 17 divide by 3 to leave a remainder of 2

Step 3

Divide each number by three to see which leaves a remainder of two:

16 梅 3 = 5 remainder 1

20 梅 3 = 6 remainder 2

19 梅 3 = 6 remainder 1

24 梅 3 = 8

25 梅 3 = 8 remainder 1

17 梅 3 = 5 remainder 2

There are only two possible numbers of magazines: 20 or 17.

Step 4

Try removing each number from the total:

137 - 20 =117

137 - 17 = 120

When you divide the answer by three, that should tell us the number of books the first customer bought

117 梅 3 = 39

120 梅 3 = 40

16, 20, 19, 24, 25 and 25 are divided by 3. Only 20 and 17 divide by 3 to leave a remainder of 2
137 -20 = 117. 117 divided by 3 equals 39. Boxes numbered 24, 25, 19, 16, 17 and 16

Step 5

Check and see if you can make this number by adding together boxes.

The remaining boxes have 24, 19, 17, 25, 16 and 16 items.

None of these can add together to make 39.

This means Eilidh did not keep 20 magazines.

137 -20 = 117. 117 divided by 3 equals 39. Boxes numbered 24, 25, 19, 16, 17 and 16
16 + 24 books = 40. 20 + 19 + 25 +16 books = 80. Eilidh the bookseller keeps 17 magazines

But 16 +24 = 40

and 20 + 19 + 25 + 16 = 80, which is 2 x 40.

This fits with the information that the second customer bought twice as many books as the first customer.

So this confirms the answer:Eilidh kept 17 magazines.

16 + 24 books = 40. 20 + 19 + 25 +16 books = 80. Eilidh the bookseller keeps 17 magazines

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