Problem 7 - Number puzzle
Problem 7 is all about working out missing numbers.
Maths teacher Chris Smith has all the answers in mind.
The Maths Week Scotland Daily Challenges have been set by the Scottish Mathematical Council.
Chris is thinking of three whole numbers.
When the first two numbers are multiplied together, he gets -6.
ab = -6
When the first and third numbers are multiplied together, he gets -8.
ac = -8
Can you work out what numbers we get when the second and third numbers are multiplied together?
bc = ?
Need a hint?
The key to unlocking this problem is working out all the possible integers that can multiply to give me the answers I was thinking of earlier.
What combinations of a and b could multiply to make -6?And what combinations of a and c could multiply to make -8?
Are there any numbers in common?
Solution
Let鈥檚 call the three unknown numbers a , b and c.
ab = -6
So a and b could be the following pairs of numbers:
1 x -6, -1 x 6
2 x -3 , -2 x 3
3 x -2, -3 x 2
6 x -1 , -6 x 1
ac = -8
This means a has to be a factor of -8.
So a can鈥檛 possibly be -6, 6, 3 or -3.
So that leaves us with four possibilities for ab = -6 and four possible pairs of values of a and b.
1 x -6, -1 x 6
2 x -3 , -2 x 3
We can then put those values into ac = -8. So ac could be:
1 x -8, -1 x 8
2 x -4, -2 x 4
We now have enough information to work out possible answers for bc = ?.
6 x 8 = 48
-6 x -8 = 48
3 x 4 = 12
-3 x -4 = 12
So there are four sets of numbers but only two solutions:
bc = 48 and bc =12.
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