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Challenge 7 - All the Ones

Challenge 7 is all about number patterns.

Maths teacher Chris Smith and pupils from Grange Academy are here to explain.

The Maths Week Scotland Daily Challenges have been set by the Scottish Mathematical Council.

So here's the challenge:

If you were to write out all the whole numbers from 1 to 1000

How many times will I write the digit 1?

the number 1 surrounded by question marks

Need a hint?

  • Can you break 1000 into smaller groups of numbers and solve these separately?
  • Could you work out how many times number one occurs in the ones, tens, and hundreds position?
  • Remember some numbers have the digit 1 more than once

Solution

Worked out the answer? Here's how you can do it.

1 to 9 = 1 10 to 19 = 11 20 to 99 = 8 subtotal = 20

Step 1

Let's chunk the 1000 numbers and check for occurrences of the digit 1.

Between 1 and 9 there is one 1

Between 10 and 19 there are 11 (remembering that 11 itself has two ones).

And between 20 and 99 there are 8 ones.

So between 1 and 99 there are 20 occurrences of the digit 1

1 to 9 = 1 10 to 19 = 11 20 to 99 = 8 subtotal = 20
200 - 299 = 20, 300 - 399 = 20, 400 - 499 = 20, 500 - 599 = 20, 600 - 699 = 20, 700 - 799 = 20, 800 - 899 = 20, 900-999 = 20

Step 2

Now that we know there are 20 ones between 1-99.

This will repeat for most of the groups of 100 numbers.

There are another 20 ones between each of these groups:

200 and 299, 300 and 399, 400 and 499, 500 and 599, 600 and 699, 700 and 799, 800 and 899, 900 and 999

That's another 8 groups of 20 ones.

200 - 299 = 20, 300 - 399 = 20, 400 - 499 = 20, 500 - 599 = 20, 600 - 699 = 20, 700 - 799 = 20, 800 - 899 = 20, 900-999 = 20
100 - 109 = 11, 110 - 119 = 21, 120 - 199 = 88, subtotal = 120

Step 3

There are more than 20 ones between 100 and 199 because each of these numbers starts with with a one.

Between 100 and 109 there are 11 ones

Between 110 and 119 there are 21 (remembering that 111 itself has three ones).

Between 120 and 199 there are another 88

So we have a total of 120 ones between 100 and 199.

100 - 109 = 11, 110 - 119 = 21, 120 - 199 = 88, subtotal = 120
20 x 9 + 120 + 1 = 301

Step 4

Don鈥檛 forget the 1 in 1000!

We can now find the total:

20 x 9 + 120 +1 = 301

There are 301 ones between 1 and 1000.

20 x 9 + 120 + 1 = 301

Alternative solution

You can also find the answer by working out the number of ones for each place value:

  • There are 100 numbers with 1 in the ones (units) position

  • 100 numbers with 1 in the tens position

  • 100 numbers with 1 in the hundreds position

  • And 1 number with 1 in the thousands position

100 + 100 + 100 + 1 = 301

Which gives us the same total of 301 ones.

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